Semiconductor Troubleshooting MCQ Quiz Part 2 of 5 | 50 Questions

Semiconductor Troubleshooting MCQ Quiz — Part 2 of 5

Transistors — BJT, FET & Handling | 50 Practice Questions (Q51–Q100 of 250) | For ITI Electrician, Electronics Mechanic, Diploma ECE/EEE and industrial electronics maintenance trainees

Topic Focus: Transistors — BJT, FET & Handling
Covers BJT structure/biasing/regions of operation, CE/CB/CC configurations, thermal runaway, Darlington pairs, JFET/MOSFET theory, ESD handling, and transistor testing with a multimeter.
This is Part 2 of a 5-part, 250-question Semiconductor Troubleshooting practice series covering real-world fault-diagnosis scenarios.

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Source basis: Standard semiconductor device physics and practical electronics troubleshooting principles as taught in ITI/Diploma electronics curricula, consistent with well-established component references (diode/transistor datasheets, IC families and standard test procedures). Prepared for practice and skill-building purposes; always follow your equipment manufacturer's manual and workplace safety procedures.

About this practice set

This page is Part 2 of 5 in the Semiconductor Troubleshooting MCQ Quiz series. It contains 50 multiple-choice questions (Q51 to Q100 of the 250-question set) on Transistors — BJT, FET & Handling. The questions are written for ITI, diploma and B.Tech trainees and for anyone preparing for a maintenance or fault-finding interview. Each question has four options; the quiz above checks your answer and shows an explanation, and the full answer key is printed below so you can also revise without running the quiz.

How to use this quiz

  1. Attempt the questions in one sitting without searching for answers.
  2. Read the explanation shown after each answer, even when you were right.
  3. Write down the questions you missed and the reason in your own words.
  4. Open the answer key below to revise those questions.
  5. Retake the quiz after a day or two and compare your score.

Sample of what is covered

  • What does the abbreviation BJT stand for?
  • Why is the base region of a BJT made physically very thin and lightly doped?
  • What is the approximate voltage gain of a common-collector (emitter-follower) amplifier configuration?
  • What is 'thermal runaway' in a BJT operating circuit?
  • If a transistor's base-emitter junction shows an OL (open) reading in diode-test mode in the direction that should normally forward bias it, what does this indicate?
  • What does the term MOSFET stand for?
  • What primarily causes distortion (clipping) in a common-emitter amplifier output waveform?
  • Compared to BJTs, JFETs are often preferred in low-noise, sensitive input amplifier stages primarily because of what characteristic?

Answer key with explanations (50 questions)

Q1. What does the abbreviation BJT stand for?

A. Bias Junction Terminal

B. Basic Junction Thyristor

C. Binary Junction Transducer

D. Bipolar Junction Transistor ✓ Correct answer

Explanation: A BJT is called 'bipolar' because both electrons and holes contribute to current conduction, unlike a FET which uses only one type of charge carrier.
Q2. In an NPN transistor operating normally as an amplifier, what is the bias condition of its two junctions?

A. Both junctions are reverse biased

B. The collector-base junction is forward biased and the emitter-base junction is reverse biased

C. Both junctions are forward biased

D. The emitter-base junction is forward biased and the collector-base junction is reverse biased ✓ Correct answer

Explanation: For active-region operation, the emitter-base junction must be forward biased to inject carriers into the base, while the collector-base junction stays reverse biased to collect them without conducting significantly on its own.
Q3. Which terminal of a BJT is the most heavily doped and supplies the majority of charge carriers?

A. The emitter ✓ Correct answer

B. All three are doped equally

C. The collector

D. The base

Explanation: The emitter is doped most heavily so that it can inject a large number of majority carriers into the thin base region, which is essential for the transistor's current-amplifying action.
Q4. Which relationship correctly describes the currents in a BJT?

A. IE = IB + IC (emitter current equals the sum of base and collector current) ✓ Correct answer

B. IC = IE + IB

C. IE = IC - IB

D. IB = IE + IC

Explanation: By Kirchhoff's current law applied to the transistor, all the current entering through the emitter must leave through the base and collector combined, so IE = IB + IC.
Q5. What does the current gain 'beta' (hFE) of a BJT represent?

A. The voltage gain of the transistor

B. The ratio of collector current to base current (IC/IB) ✓ Correct answer

C. The ratio of collector current to emitter current (IC/IE)

D. The ratio of base current to emitter current (IB/IE)

Explanation: Beta (hFE) indicates how many times larger the collector current is compared to the small base current that controls it, which is the transistor's basic current-amplification factor.
Q6. A transistor with a very high beta (hFE) value implies what?

A. A very small base current can control a much larger collector current ✓ Correct answer

B. The base-emitter junction is permanently reverse biased

C. The transistor cannot be used for amplification

D. The transistor will always operate in cutoff

Explanation: High beta means high current gain, so only a tiny base current is needed to drive a proportionally much larger collector current, useful for sensitive switching and amplifier stages.
Q7. Why is the base region of a BJT made physically very thin and lightly doped?

A. So that most carriers injected from the emitter pass through to the collector instead of recombining in the base ✓ Correct answer

B. So that the base can carry the majority of the transistor's total current

C. To increase the transistor's breakdown voltage rating

D. To prevent the transistor from conducting at all

Explanation: A thin, lightly doped base allows the vast majority of emitter-injected carriers to be swept across to the collector before they can recombine, which is what gives the transistor its current gain.
Q8. For a BJT to operate in its active (linear amplifying) region, what bias condition must exist?

A. Both junctions forward biased

B. Both junctions reverse biased

C. Emitter-base junction reverse biased and collector-base junction forward biased

D. Emitter-base junction forward biased and collector-base junction reverse biased ✓ Correct answer

Explanation: This specific combination lets the base inject carriers that the collector then collects proportionally, producing an output current that varies linearly with the small input base current or voltage.
Q9. What bias condition puts a BJT into saturation, where it behaves like a fully closed (ON) switch?

A. Only the collector-base junction is forward biased

B. The base is left floating (disconnected)

C. Both junctions are reverse biased

D. Both the emitter-base and collector-base junctions are forward biased ✓ Correct answer

Explanation: In saturation both junctions conduct, the collector-emitter voltage drops to a very low value, and the transistor offers minimal resistance, acting like a closed switch carrying maximum current for the given circuit.
Q10. What bias condition puts a BJT into cutoff, where it behaves like a fully open (OFF) switch?

A. The collector is shorted to the emitter

B. Both the emitter-base and collector-base junctions are reverse biased ✓ Correct answer

C. Only the emitter-base junction is forward biased

D. Both junctions are forward biased

Explanation: In cutoff neither junction conducts, so essentially no collector current flows and nearly the full supply voltage appears across the collector-emitter terminals, just like an open switch.
Q11. In a transistor switching circuit, what is the primary purpose of the base resistor?

A. To increase the transistor's voltage gain

B. To set the collector supply voltage

C. To reverse bias the collector-base junction

D. To limit the base current to a safe value that still reliably drives the transistor into saturation ✓ Correct answer

Explanation: Without a current-limiting resistor, the low forward resistance of the base-emitter junction would allow excessive base current to flow, potentially damaging the transistor; the resistor sets a safe base current sufficient to saturate the device.
Q12. In a common-emitter amplifier, what is the phase relationship between the output signal and the input signal?

A. There is no fixed phase relationship

B. The output leads the input by 90 degrees

C. The output is inverted, 180 degrees out of phase with the input ✓ Correct answer

D. The output is exactly in phase with the input

Explanation: As the input signal on the base rises, it increases the collector current, pulling the collector voltage down through the load resistor, so the amplified output waveform is inverted relative to the input.
Q13. What is the approximate voltage gain of a common-collector (emitter-follower) amplifier configuration?

A. Very high, often several hundred, with phase inversion

B. Negative and less than -1

C. Approximately 1 (unity), with no phase inversion ✓ Correct answer

D. Exactly zero under all conditions

Explanation: An emitter follower's output voltage closely tracks its input voltage because the emitter resistor provides near-total negative feedback; it instead provides high current gain and low output impedance, making it useful as a buffer stage.
Q14. Which amplifier configuration is typically used mainly for impedance matching and buffering rather than voltage gain?

A. Common collector (emitter follower) ✓ Correct answer

B. Common emitter

C. None of these provide impedance matching

D. Common base with high voltage gain

Explanation: The emitter follower presents a high input impedance and a low output impedance with near-unity voltage gain, making it ideal for isolating a high-impedance source from a low-impedance load.
Q15. What does the 'Q-point' (quiescent operating point) of a transistor amplifier refer to?

A. The transistor's maximum power rating

B. The DC bias condition (base current, collector current, and collector-emitter voltage) with no AC signal applied ✓ Correct answer

C. The peak AC output voltage during operation

D. The exact moment the transistor switches fully on

Explanation: The Q-point defines the transistor's DC operating conditions before any AC signal is superimposed, and it must be set in the middle of the active region for undistorted, maximum-swing amplification.
Q16. Why is a fixed (base) bias circuit generally considered a poor choice for a practical transistor amplifier?

A. It gives perfectly stable bias regardless of transistor replacement

B. It requires no resistors at all to implement

C. It provides very poor thermal stability, allowing the Q-point to drift significantly with temperature and beta variation ✓ Correct answer

D. It only works with PNP transistors, never NPN

Explanation: Fixed bias sets base current with a single resistor from the supply, so any change in beta or temperature directly shifts the collector current and Q-point, risking thermal runaway or distorted output.
Q17. What is the main advantage of voltage-divider bias over simple fixed bias in a transistor amplifier?

A. It eliminates the need for a collector resistor

B. It doubles the transistor's maximum voltage rating

C. It provides a stable Q-point that is largely independent of variations in the transistor's beta ✓ Correct answer

D. It removes the need for any power supply

Explanation: By fixing the base voltage with a resistor divider and adding an emitter resistor for feedback, voltage-divider bias keeps the operating point stable even when beta varies between individual transistors or with temperature.
Q18. What is the function of the emitter resistor in a voltage-divider biased amplifier stage?

A. It has no effect on bias stability

B. It increases the transistor's current gain beyond its rated beta

C. It reverse biases the base-emitter junction permanently

D. It provides negative feedback that stabilizes the Q-point against temperature and beta variations ✓ Correct answer

Explanation: If collector current tends to rise, for example due to heat, the emitter voltage rises too, which reduces the effective base-emitter forward bias and pulls the current back down, a self-correcting negative feedback action.
Q19. What is 'thermal runaway' in a BJT operating circuit?

A. A destructive cycle where rising temperature increases collector current, which generates more heat, further increasing current until the transistor is damaged ✓ Correct answer

B. A phenomenon that only affects FETs, not BJTs

C. A normal and desirable characteristic of all amplifier circuits

D. A condition where the transistor cools itself as current increases

Explanation: As a BJT heats up, its collector current tends to increase for a given bias, generating more heat and further increasing current; without adequate bias stabilization such as an emitter resistor, this positive feedback loop can destroy the device.
Q20. What is the main purpose of attaching a heat sink to a power transistor?

A. To increase the transistor's current gain

B. To increase the surface area for dissipating heat, keeping the junction temperature within safe limits ✓ Correct answer

C. To electrically insulate the transistor from the circuit

D. To reduce the transistor's switching speed intentionally

Explanation: Power transistors dissipate significant heat during operation; a heat sink provides a larger surface area, often with fins, to conduct that heat away into the surrounding air, preventing thermal damage.
Q21. What is a Darlington pair?

A. A single transistor with two collectors

B. Two transistors connected in parallel to share load current equally with no gain change

C. A transistor combined with a Zener diode for voltage regulation

D. Two transistors connected so the emitter of the first drives the base of the second, giving a very high combined current gain ✓ Correct answer

Explanation: In a Darlington configuration the overall current gain is approximately the product of the two individual transistors' betas, allowing a very small base current to control a much larger load current.
Q22. When testing an NPN transistor's base-emitter junction with a multimeter in diode-test mode, which probe connection should show a forward voltage drop reading?

A. Black probe on the base, red probe on the emitter

B. Neither connection should show any reading

C. Red probe on the base, black probe on the emitter ✓ Correct answer

D. Red probe on the collector, black probe on the base

Explanation: In an NPN transistor the base-emitter junction behaves like a diode with the base as its anode, so applying the meter's positive (red) lead to the base and negative (black) lead to the emitter forward biases it and shows a normal drop, typically 0.5-0.7 V.
Q23. For a PNP transistor, how does diode-mode testing of the junctions differ from testing an NPN transistor?

A. PNP transistors cannot be tested with a multimeter

B. Only the collector-emitter junction can be tested on a PNP transistor

C. The probe polarity is reversed; the black (negative) probe on the base shows forward conduction to the emitter and collector ✓ Correct answer

D. There is no difference at all between NPN and PNP testing

Explanation: Because a PNP transistor's base acts like the cathode of the two internal diode junctions, the black probe must go on the base while the red probe touches the emitter or collector to see a normal forward voltage drop.
Q24. If a suspected faulty transistor shows a very low resistance, near a dead short, between collector and emitter in both polarity directions, what does this suggest?

A. The transistor is a healthy PNP type only

B. The transistor has internally shorted and must be replaced ✓ Correct answer

C. The multimeter is set to the wrong voltage range

D. The transistor is functioning completely normally

Explanation: A healthy transistor's collector-emitter path should show high resistance when not conducting (base open); a near-zero reading in both directions typically means the junctions have broken down and shorted internally.
Q25. If a transistor's base-emitter junction shows an OL (open) reading in diode-test mode in the direction that should normally forward bias it, what does this indicate?

A. The meter needs to be switched to AC voltage mode

B. The junction is open-circuited internally and the transistor has failed ✓ Correct answer

C. The transistor is working exactly as expected

D. The transistor is a Darlington pair

Explanation: A good transistor should always show a normal forward voltage drop across a properly polarity-matched base-emitter junction; an open reading there means that junction has failed open, usually from excess current or voltage.
Q26. What does the term FET stand for, and how does it fundamentally differ from a BJT in terms of control?

A. Forward-Emission Transistor; it only works in reverse bias

B. Frequency-Enhanced Transistor; it requires an AC-only supply

C. Fixed-Emitter Transistor; it is identical in operation to a BJT

D. Field-Effect Transistor; it is voltage-controlled rather than current-controlled like a BJT ✓ Correct answer

Explanation: A FET's channel conductivity is controlled by an electric field from the gate voltage, drawing essentially no steady gate current, whereas a BJT's collector current is controlled by a base current.
Q27. Compared to a BJT, a FET (such as a JFET or MOSFET) typically has what kind of input impedance?

A. Much lower input impedance

B. Input impedance is not a meaningful FET parameter

C. Exactly the same input impedance as a BJT

D. Much higher input impedance ✓ Correct answer

Explanation: Because the FET's gate is either reverse biased (JFET) or insulated by an oxide layer (MOSFET), it draws negligible input current, giving it an input impedance many orders of magnitude higher than a BJT's.
Q28. In a JFET, what controls the width, and hence resistance, of the conducting channel between source and drain?

A. The forward current flowing into the gate terminal

B. The temperature of the drain terminal only

C. The physical rotation of the device

D. The reverse-bias voltage applied to the gate, which controls the width of the depletion region extending into the channel ✓ Correct answer

Explanation: As gate-to-source reverse bias increases, the depletion region around the gate-channel junction widens and narrows the conducting channel, reducing drain current; this voltage control is the basic operating principle of a JFET.
Q29. What is 'pinch-off voltage' in a JFET?

A. The gate-source voltage at which the channel becomes fully depleted and drain current is reduced to a very small value ✓ Correct answer

B. The supply voltage required to turn the JFET fully on

C. The voltage at which the JFET permanently short circuits

D. The forward voltage drop of the gate-channel junction

Explanation: As gate reverse bias approaches the pinch-off voltage, the depletion regions from both sides of the channel meet, severely restricting current flow and marking the boundary of the JFET's usable operating region.
Q30. For a standard n-channel JFET, what is the normal biasing polarity of the gate-source voltage during operation?

A. Zero volts at all times, never varied

B. Negative, meaning the gate is reverse biased with respect to the source ✓ Correct answer

C. Alternating polarity every half cycle regardless of application

D. Positive and forward biased

Explanation: An n-channel JFET's gate-channel junction must stay reverse biased to maintain very high input impedance and proper control of the depletion region, so the gate is normally held negative relative to the source.
Q31. What does the term MOSFET stand for?

A. Mechanically Operated Switching Field-Effect Transistor

B. Metal-Oxide-Semiconductor Field-Effect Transistor ✓ Correct answer

C. Modulated Oscillation Semiconductor Field-Effect Type

D. Multi-Output Semiconductor Field-Effect Terminal

Explanation: The name describes its physical construction: a metal (or polysilicon) gate electrode separated from the semiconductor channel by a thin insulating oxide layer.
Q32. What gives a MOSFET its extremely high input (gate) impedance compared to a JFET?

A. The gate is completely insulated from the channel by a thin oxide layer, so essentially no DC current flows into the gate ✓ Correct answer

B. The gate is made of a special high-resistance metal alloy

C. The gate is directly connected to the source internally

D. MOSFETs actually have lower input impedance than JFETs

Explanation: Because the gate is separated from the channel by an insulating silicon dioxide layer rather than a reverse-biased PN junction, the MOSFET draws virtually no steady-state gate current, giving input impedance in the range of teraohms.
Q33. An enhancement-mode MOSFET is normally in what state with zero gate-source voltage applied?

A. OFF, since no conducting channel exists until a sufficient gate voltage is applied to create one ✓ Correct answer

B. Permanently damaged if gate voltage is zero

C. ON, fully conducting until switched off by gate voltage

D. Always in saturation regardless of gate voltage

Explanation: In enhancement-mode devices, no channel exists at zero gate bias; applying a gate voltage beyond the threshold voltage attracts charge carriers that form (enhance) a conducting channel, turning the device on.
Q34. A depletion-mode MOSFET is normally in what state with zero gate-source voltage applied?

A. It behaves identically to an enhancement-mode device in every way

B. It cannot conduct current under any bias condition

C. ON, because a conducting channel already exists and gate voltage can be used to deplete (reduce) it ✓ Correct answer

D. OFF, since it requires a gate voltage to create any channel at all

Explanation: Depletion-mode MOSFETs are manufactured with a channel already physically present, so current flows at zero gate bias; applying gate voltage of the appropriate polarity depletes carriers from this channel and reduces conduction.
Q35. Why are MOSFETs generally considered highly sensitive to electrostatic discharge (ESD) damage?

A. Static discharge only affects the MOSFET's case, never its internal structure

B. MOSFETs conduct static electricity better than any other component

C. The extremely thin gate oxide layer can be permanently punctured by the high voltages present in static discharges ✓ Correct answer

D. MOSFETs have no protective packaging of any kind

Explanation: Static discharge can momentarily reach several thousand volts; because the gate oxide is only a few atoms thick, this voltage can easily break down and permanently puncture the insulating layer, destroying the device.
Q36. What ESD precaution is recommended when storing or handling loose MOSFETs before they are installed in a circuit?

A. Store them loosely in a plastic bag with leads separated and exposed

B. Apply power to the device before touching its leads

C. Keep the leads shorted together, for example in conductive foam, and use a grounded wrist strap when handling them ✓ Correct answer

D. Handle them only while standing on a carpeted floor

Explanation: Shorting the leads together equalizes any charge across the terminals so no damaging voltage difference can build up across the gate oxide, and a grounded wrist strap prevents the handler's own static charge from reaching the device.
Q37. What primarily causes distortion (clipping) in a common-emitter amplifier output waveform?

A. The transistor having too high a current gain for any input signal

B. The Q-point being poorly centered or the input signal amplitude being too large, driving the transistor into saturation or cutoff ✓ Correct answer

C. Using a well-centered Q-point with a small input signal

D. The load resistor value being exactly matched to the source impedance

Explanation: If the Q-point sits too close to saturation or cutoff, or if the input swing is too large, part of the output waveform gets driven into that nonlinear region and is clipped flat, distorting the amplified signal.
Q38. What is the typical base-emitter forward voltage (VBE) required for a silicon BJT to conduct in its active region?

A. Approximately 0.2 V

B. Approximately 12 V

C. Approximately 5 V

D. Approximately 0.6 to 0.7 V ✓ Correct answer

Explanation: Like any silicon PN junction, the base-emitter junction of a silicon transistor needs roughly 0.6-0.7 V of forward bias before it conducts appreciably and the transistor can amplify or switch.
Q39. A 'leaky' transistor with abnormally high collector-to-emitter leakage current (ICEO) in a switching circuit can cause what practical problem?

A. It has no measurable effect on circuit behavior

B. The circuit will draw exactly zero current under all conditions

C. The transistor may appear to be partially or fully 'on' even when it should be fully off, causing unintended load activation or excess heat ✓ Correct answer

D. The transistor will always show a perfectly open circuit reading

Explanation: Excessive leakage current lets some current flow through the transistor even when it is supposed to be cut off, which can partially energize a load, waste power as heat, or in extreme cases keep the load continuously on.
Q40. A power transistor used as a switch is found permanently conducting, collector shorted to emitter, even with zero base drive. What is the most likely internal fault?

A. The load resistor is open circuit

B. The transistor has failed with an internal collector-emitter short ✓ Correct answer

C. The supply voltage polarity is reversed

D. The base resistor value is too small

Explanation: If removing all base drive still leaves the collector and emitter effectively connected, the transistor's internal junctions have broken down and shorted, and the component must be replaced rather than the surrounding circuitry.
Q41. A transistor switch circuit never turns its load on, even with correct base drive voltage and current present. What internal transistor fault should be suspected?

A. The transistor is a Darlington pair

B. An open circuit within one of the transistor's internal junctions, such as an open base-emitter junction ✓ Correct answer

C. The transistor's current gain (beta) is too high

D. The transistor's collector-emitter junction has shorted

Explanation: If proper base drive is confirmed present but the load never switches on, an internally open junction prevents any collector current from flowing regardless of the input signal, and the transistor should be tested and likely replaced.
Q42. What device is commonly used to directly measure a transistor's hFE (current gain) using a dedicated multimeter test socket?

A. A clamp meter measuring AC current only

B. An oscilloscope probe alone

C. A standard analog wattmeter

D. A multimeter with a built-in transistor-tester (hFE) socket ✓ Correct answer

Explanation: Many multimeters include a small socket with labeled pin positions (E, B, C) for NPN and PNP transistors that applies a known base current and displays the resulting hFE value directly.
Q43. Compared to BJTs, JFETs are often preferred in low-noise, sensitive input amplifier stages primarily because of what characteristic?

A. JFETs require no biasing at all to operate

B. JFETs always provide much higher voltage gain than any BJT circuit

C. JFETs generally exhibit lower input noise and draw negligible gate current, reducing loading effects on sensitive sources ✓ Correct answer

D. JFETs cannot be damaged by static electricity, unlike BJTs

Explanation: A JFET's very high input impedance means it barely loads a high-impedance signal source, and its noise characteristics are often favorable for the front end of instrumentation and audio preamplifier circuits.
Q44. What is a key advantage of using a power MOSFET instead of a BJT as a switching device in circuits like inverters or motor drivers?

A. A MOSFET is voltage-driven and needs virtually no continuous gate current, simplifying drive circuitry and reducing drive power loss ✓ Correct answer

B. A MOSFET cannot be damaged by excessive drain current under any condition

C. A MOSFET requires a continuous base current proportional to load current, just like a BJT

D. A MOSFET always has a lower voltage rating than any comparable BJT

Explanation: Because the MOSFET gate is capacitive rather than resistive, once charged to the correct voltage it needs almost no steady current to stay on, unlike a BJT which needs continuous base current proportional to the load; this simplifies and improves the efficiency of drive circuits.
Q45. What is the common-base amplifier configuration primarily known for, compared to common-emitter?

A. High voltage gain but a current gain of less than 1, along with very low input impedance and no phase inversion ✓ Correct answer

B. Always producing a 180-degree phase-inverted output

C. Extremely high input impedance, higher than common-collector

D. The highest current gain of all three configurations

Explanation: In common-base configuration, output current is always slightly less than input (emitter) current, so current gain is under unity, but voltage gain can be high; the input and output signals remain in phase, unlike common-emitter.
Q46. Why must the collector supply voltage and load resistor be chosen so the transistor's maximum collector current and power dissipation ratings are not exceeded?

A. Manufacturers design all transistors to tolerate unlimited current safely

B. Exceeding these ratings can cause excessive heat buildup and permanent damage to the transistor junction ✓ Correct answer

C. The transistor's beta value automatically adjusts to prevent any overcurrent condition

D. Exceeding the ratings only affects the transistor's color coding, not its function

Explanation: Every transistor has maximum ratings for collector current, collector-emitter voltage, and total power dissipation; operating beyond any of these generates excess heat that can destroy the junction structure.
Q47. What role does an emitter-follower (common-collector) buffer stage commonly play between a high-impedance source and a low-impedance load, such as a speaker?

A. It inverts the phase of the signal by 180 degrees before the load

B. It converts the AC signal into a regulated DC voltage

C. It boosts the voltage of the signal by a large factor before the load

D. It matches impedance and supplies the current gain needed to drive the low-impedance load without loading down the source ✓ Correct answer

Explanation: Because the emitter follower has high input impedance and low output impedance with near-unity voltage gain, it isolates a sensitive source from a demanding load while providing the current drive that low-impedance loads require.
Q48. What visual/physical clue commonly helps identify the collector, base, and emitter leads on a TO-92 package small-signal transistor, aside from testing?

A. The lead order is universally identical for every TO-92 transistor ever made

B. The flat face of the package always indicates the emitter lead only, regardless of part number

C. The leads are always color-coded red, black, and green

D. The manufacturer's datasheet pinout diagram, since lead order can vary between transistor types and manufacturers ✓ Correct answer

Explanation: Unlike diodes with a universal cathode band convention, transistor pin arrangements vary between manufacturers and part numbers, so the datasheet is the reliable source for pin identification rather than assuming a fixed pattern.
Q49. In power electronics, why is it common practice to insulate a power transistor's metal tab from a grounded heatsink using a mica washer and thermal compound?

A. Thermal compound is used only for cosmetic purposes

B. Mica washers improve the transistor's current gain

C. The transistor's collector may be internally connected to the metal tab, so insulation prevents an unwanted electrical connection to the grounded heatsink while still conducting heat ✓ Correct answer

D. Insulation is required to prevent the heatsink from melting

Explanation: In many power transistor packages the collector is electrically tied to the metal mounting tab; a thin mica or silicone insulator with thermal compound conducts heat to the heatsink while electrically isolating the collector from it and from other mounted devices.
Q50. Which biasing configuration connects a resistor directly from the collector to the base, providing a degree of self-stabilizing negative feedback against beta variation?

A. Pure emitter bias with a dual supply only

B. Fixed base bias with no feedback resistor

C. Zener diode bias applied to the collector only

D. Collector-to-base bias (collector feedback bias) ✓ Correct answer

Explanation: If collector current rises, the collector voltage falls, which reduces the base current fed back through the collector-base resistor, pulling collector current back down, a simple form of negative feedback that improves bias stability over fixed bias.

Frequently asked questions

Who is this Semiconductor Troubleshooting quiz for?

It is for ITI, diploma and B.Tech students, apprentices and working technicians who want to test fault-finding knowledge. The explanations are written to teach the reason, not just the answer.

How should I use the answer key?

Attempt the quiz first without looking. Then open the answer key, read the explanation for every question you missed, and retake the part after a day to see whether the explanation stuck.

Do I need to finish all five parts?

No, but the parts build on one another: fundamentals first, then components, then circuits and real-world scenarios. Part 5 is the best test of whether you can apply the earlier parts to a live fault.

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